Lean, informalized

Nielsen & Chuang · Chapter 2, Introduction to quantum mechanics · p. 66

Exercise 2.6 - Amplitudes in the first slot of an inner product come out complex conjugated

An inner product is conjugate linear in its first argument.

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The Exercise

Take vectors |w1⟩,…,|wn⟩|w_1\rangle, \dots, |w_n\rangle and |v⟩|v\rangle of an inner product space, and complex amplitudes λ1,…,λn\lambda_1, \dots, \lambda_n. Write (|a⟩,|b⟩)(|a\rangle, |b\rangle) for the inner product of |a⟩|a\rangle with |b⟩|b\rangle. Exercise 2.6 asks to show that any inner product is conjugate linear in its first argument: when the superposition ∑iλi|wi⟩\sum_i \lambda_i |w_i\rangle stands in the first slot, against |v⟩|v\rangle in the second, each amplitude comes out as its complex conjugate λi*\lambda_i^*.✦

The Claim

Theorem 1. Let VV be an inner product space over 𝕂\mathbb{K}, the real or the complex numbers, and write λ*\lambda^* for the complex conjugate of a scalar λ\lambda. Let SS be a finite set of indices, with a scalar λi\lambda_i and a vector |wi⟩|w_i\rangle of VV for each i∈Si \in S, and let |v⟩|v\rangle be a vector of VV. Then (∑i∈Sλi|wi⟩,|v⟩)=∑i∈Sλi*(|wi⟩,|v⟩).\Bigl(\sum_{i \in S} \lambda_i |w_i\rangle,\, |v\rangle\Bigr) = \sum_{i \in S} \lambda_i^* \, \bigl(|w_i\rangle, |v\rangle\bigr).(1)✦

With 𝕂\mathbb{K} the complex numbers this is the exercise.

What Is Checked

The |wi⟩|w_i\rangle need not be normalized or orthogonal. For every such choice the library proves the identity (1).