Lean, informalized

Nielsen & Chuang · Chapter 2, Introduction to quantum mechanics · p. 71

Exercise 2.18 - Every eigenvalue of a unitary operator on a Hilbert space has modulus one

Eigenvalues of a unitary have modulus one.

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The Exercise

The evolution of a closed quantum system over a fixed time is a unitary operator UU on its state space, and a state that UU only rescales is an eigenvector of UU. The exercise asks what the scale factor can be: every eigenvalue of a unitary operator has modulus one, so such a state changes by a phase and nothing more.

Unitary Operators and Eigenvalues

The library states the claim on any Hilbert space HH, over the real or the complex numbers, of finite or infinite dimension.

A unitary operator UU on HH is a bounded linear operator on HH whose adjoint is its inverse: U†U=UU†=I.U^\dagger U = U U^\dagger = I .(1)

An eigenvalue μ\mu of a linear operator UU on HH is a scalar for which some nonzero vector |ψ⟩|\psi\rangle of HH satisfies U|ψ⟩=μ|ψ⟩.U|\psi\rangle = \mu\,|\psi\rangle .(2)

The Claim

Theorem 1. Let HH be a Hilbert space and UU a unitary operator on HH. Every eigenvalue μ\mu of UU has modulus one: |μ|=1.|\mu| = 1 .(3)✦

What Is Checked

The claim is stated over a unitary operator UU on a Hilbert space HH, as in (1), and an eigenvalue μ\mu of UU, as in (2). What the library proves about these constructions is the theorem itself, with no hypothesis beyond the two definitions.