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Nielsen & Chuang · Chapter 11, Entropy and information · p. 514

Exercise 11.13 - The von Neumann entropy of a product state is the sum of the entropies of its factors

Entropy adds over independent systems.

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The Exercise

Two quantum systems AA and BB are prepared apart from each other, AA in a state ρ\rho and BB in a state σ\sigma, so that the pair carries no correlation and is described by the tensor product ρ⊗σ\rho \otimes \sigma of the two density operators. The exercise asks how the von Neumann entropy of the pair is related to the entropies of its two parts.

Systems and States

A quantum system AA is a physical system whose state space ℋA\mathcal{H}_A is a finite dimensional complex Hilbert space.✦ The composite system A⊗BA \otimes B of two quantum systems AA and BB is the quantum system whose state space is the tensor product of theirs, ℋA⊗B=ℋA⊗ℋB.\mathcal{H}_{A \otimes B} = \mathcal{H}_A \otimes \mathcal{H}_B .(1)✦

A state ρ\rho of AA is a positive operator of unit trace on ℋA\mathcal{H}_A.✦

The product state ρ⊗σ\rho \otimes \sigma of a state ρ\rho of AA and a state σ\sigma of BB is the state of A⊗BA \otimes B whose density operator is the tensor product of the two, acting as ρ\rho on the first factor and as σ\sigma on the second: (ρ⊗σ)(|a⟩⊗|b⟩)=ρ|a⟩⊗σ|b⟩,|a⟩∈ℋA,|b⟩∈ℋB.(\rho \otimes \sigma)\bigl(|a\rangle \otimes |b\rangle\bigr) = \rho|a\rangle \otimes \sigma|b\rangle , \qquad |a\rangle \in \mathcal{H}_A ,\ |b\rangle \in \mathcal{H}_B .(2)✦

The Entropy of a State

The von Neumann entropy of a state ρ\rho of AA is the real number S(ρ)=−tr⁡(ρln⁡ρ)=−∑iλiln⁡λi,S(\rho) = -\operatorname{tr}(\rho \ln \rho) = -\sum_i \lambda_i \ln \lambda_i ,(3)✦ the Shannon entropy of the nonzero eigenvalues λi\lambda_i of ρ\rho. The logarithm is natural, so entropy is measured in nats.

The Claim

Theorem 1. Let ρ\rho be a state of a quantum system AA and σ\sigma a state of a quantum system BB. Then the product state ρ⊗σ\rho \otimes \sigma of the composite system A⊗BA \otimes B has von Neumann entropy S(ρ⊗σ)=S(ρ)+S(σ).S(\rho \otimes \sigma) = S(\rho) + S(\sigma).(4)✦

What Is Checked

The claim is stated over any two quantum systems AA and BB and any states ρ\rho of AA and σ\sigma of BB.

About these constructions the library proves that the tensor product of two density operators is again positive with unit trace, so that ρ⊗σ\rho \otimes \sigma is a state of A⊗BA \otimes B.